Problem:
A rectangular frame ABCD made of auniform metal wire has a straight connection between E & F made of the same wire as shown in the figure. AEFD is a square of side 1 m & EB = FC = 0.5 m. The entire circuit is placed in a steadily increasing uniform magnetic field directed into the place ofthe paper & normal to it. The rate of change of the magnetic field is 1 T/s, the resistance per unit length ofthe wire is 1 \Omega/m. Find the current in segments AE, BE & EF. [IIT JEE'93]
No comments:
Post a Comment